(x+1)^1/2=x

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Solution for (x+1)^1/2=x equation: 


x in (-oo:+oo)

((x+1)^1)/2 = x // - x

((x+1)^1)/2-x = 0

(x+1)/2-x = 0

(x+1)/2+(2*(-x))/2 = 0

x+2*(-x)+1 = 0

1-x = 0

(1-x)/2 = 0

(1-x)/2 = 0 // * 2

1-x = 0

1-x = 0 // - 1

-x = -1 // * -1

x = 1

x = 1

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